Question
Two trains started from stations βAβ and βBβ at
same time and started travelling towards each other at speeds of 60 km/hr and 50 km/hr, respectively. At the time of their meeting, the faster train has travelled 122 km more than the slower train. Find the distance between the stations βA and βBβ.Solution
Let the distance travelled by slower train be βxβ km So, distance travelled by faster train = βx + 122β km ATQ, (x/50) = {(x + 122)/60} Or, 60x = 50x + 6100 Or, 10x = 6100 So, x = 610 Total distance between station βAβ and station βBβ = (610 + 610 + 122) = 1342 km
At the BCCI Awards 2024 in Hyderabad, who was honored with the Lifetime Achievement Award?
What is the key objective of ISRO's "Young Scientist Programme" (YUVIKA)?
Recently Union Minister for Jal Shakti Shri Gajendra Singh Shekhawat on 15th December 2022 inaugurated the 7th Edition of the India Water Impact Summit ...
What is the primary benefit of the property card issued under the SVAMITVA scheme?
Recently Which of the following giant tortoise species was discovered after a century?
Which bank introduced a 'Mobile Handheld Device' to enhance accessibility and convenience?
The Pradhan Mantri Annadata Aay SanraksHan Abhiyan (PM-AASHA) includes a component for procuring pulses and oilseeds at MSP. Which of the following crop...
What was the theme of World Telecommunication Day 2025?
What is the length of recently inaugurated Bundelkhand expressway will connect Chitrakoot in the underdeveloped Bundelkhand region with the Lucknow - A...
The rating agency ICRA announced the appointment of __________ as managing director and group chief executive officer.