Question
Two trains started from stations βAβ and βBβ at
same time and started travelling towards each other at speeds of 60 km/hr and 50 km/hr, respectively. At the time of their meeting, the faster train has travelled 122 km more than the slower train. Find the distance between the stations βA and βBβ.Solution
Let the distance travelled by slower train be βxβ km So, distance travelled by faster train = βx + 122β km ATQ, (x/50) = {(x + 122)/60} Or, 60x = 50x + 6100 Or, 10x = 6100 So, x = 610 Total distance between station βAβ and station βBβ = (610 + 610 + 122) = 1342 km
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