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Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 122’ km ATQ, (x/50) = {(x + 122)/60} Or, 60x = 50x + 6100 Or, 10x = 6100 So, x = 610 Total distance between station ‘A’ and station ‘B’ = (610 + 610 + 122) = 1342 km
(2 ÷ 3) × (4 ÷ 12) × (? ÷ 10) × 45 × (1 ÷ 5) = (? ÷ 6) + (2 ÷ 5)
(3984 ÷ 24) x (5862 ÷ 40) = ?
641.5 + 72 × 8 = ? × 4
What will come in place of (?) in the given expression.
{(60% of 250) + √144} ÷ (3² - 4) = ?
72% of 486 – 64% of 261 = ?
[√441 ÷7] × 40% of ? = 500 – 12.5% of 400
240 × 2.5 + 65 × 2/13 = ?2 - √225