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ATQ,
Let the speed of train 'P' be 'x' km/h
Distance covered by train 'P' alone = 2 × x = 2x km
Time both trains travelled together = 5 hours
ATQ;
5 × (55 + x) = 620 - 2x
Or, 275 + 5x = 620 - 2x
Or, 345 = 7x
So, x = 49.29
So, speed of train 'P' = 49.29 km/h
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