Question
Train 'P' leaves Pune for Nagpur at 6:00 a.m. At 8:00 a.m.,
another train 'Q' departs from Nagpur to Pune at 55 km/h. Both trains meet at 1:00 p.m. If the distance between Pune and Nagpur is 620 km, what is the speed of train 'P'?Solution
ATQ,
Let the speed of train 'P' be 'x' km/h
Distance covered by train 'P' alone = 2 Γ x = 2x km
Time both trains travelled together = 5 hours
ATQ;
5 Γ (55 + x) = 620 - 2x
Or, 275 + 5x = 620 - 2x
Or, 345 = 7x
So, x = 49.29
So, speed of train 'P' = 49.29 km/h
Evaluate:
β729 + β49 - β16 + 1/β64
Simplify:

(1/5)(40% of 800 β 120) = ? Γ 5
2/5 of 3/4 of 7/9 of 7200 = ?
`sqrt(5476)` + 40% of 1640 = ? `xx` 4 - 2020
? = (22% of 25% of 60% of 3000) + 21
Determine the simplified value of the given mathematical expression.
(342 β 20% of 5280) = ? Γ· 3
β157464 =?