Question
Train βAβ travelling with a speed of 75 km/h can
cross a pole in 15 seconds. If the length of train βBβ is 24% less than that of train βAβ and it can cross a pole in 15 seconds then speed (in km/h) of train βBβ is:Solution
Speed of train βAβ = 75 Γ (5/18) = (125/6) m/s Length of train βAβ = (125/6) Γ 15 = 312.5 metres Length of train βBβ = 0.76 Γ 312.5 = 237.5 metres Speed of train βBβ = (237.5/15) Γ (18/5) = 57 km/h
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