Question
Train βAβ travelling with a speed of 72 km/h can
cross a pole in 18 seconds. If the length of train βBβ is 60% less than that of train βAβ and it can cross a pole in 12 seconds then speed (in km/h) of train βBβ is:Solution
Speed of train βAβ = 72 Γ (5/18) = 20 m/s Length of train βAβ = 20 Γ 18 = 360 metres Length of train βBβ = 0.4 Γ 360 = 144 metres Speed of train βBβ = (144/12) Γ (18/5) =216/5 Β = 43.2 km/h
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