Question
Train ‘A’ travelling with a speed of 60 km/h can
cross a pole in 15 seconds. If the length of train ‘B’ is 38% less than that of train ‘A’ and it can cross a pole in 10 seconds then speed (in km/h) of train ‘B’ is:Solution
Speed of train ‘A’ = 60 × (5/18) = (50/3) m/s Length of train ‘A’ = (50/3) × 18 = 250 metres Length of train ‘B’ = 0.62 × 250 = 155 metres Speed of train ‘B’ = (155/10) × (18/5) = 55.8 km/h
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