Question
Train βAβ travelling with a speed of 60 km/h can
cross a pole in 15 seconds. If the length of train βBβ is 38% less than that of train βAβ and it can cross a pole in 10 seconds then speed (in km/h) of train βBβ is:Solution
Speed of train βAβ = 60 Γ (5/18) = (50/3) m/s Length of train βAβ = (50/3) Γ 18 = 250 metres Length of train βBβ = 0.62 Γ 250 = 155 metres Speed of train βBβ = (155/10) Γ (18/5) = 55.8 km/h
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