Question
Train ‘A’ travelling with a speed of 60 km/h can
cross a pole in 15 seconds. If the length of train ‘B’ is 38% less than that of train ‘A’ and it can cross a pole in 10 seconds then speed (in km/h) of train ‘B’ is:Solution
Speed of train ‘A’ = 60 × (5/18) = (50/3) m/s Length of train ‘A’ = (50/3) × 18 = 250 metres Length of train ‘B’ = 0.62 × 250 = 155 metres Speed of train ‘B’ = (155/10) × (18/5) = 55.8 km/h
More Trains Questions
20 * 8 + 40% of 100 + 60% of 150 = ?
7292/3 = ?
Find the result of
45 ÷ 3 of 6 of [12 ÷ 4 of (10 ÷ 2 + 1)] + (8 ÷ 2.5 + 1.8)
- What will come in place of (?), in the given expression.
144 ÷ 12 + 18 × 2 = ? (2197)1/3 + (18)2 − 121 = ? − 69 × 5
Evaluate: {2 x (0.718 + 0.982) + 0.008 of 5000}
Simplify the following expressions and choose the correct option.
18² + (27 ÷ 3) × 11 − 250 = ?
If x²- 5x + 1 = 0, what is the value of x² + 1/x2?
? ÷ 62 × 12 = 264
