Question
Train βAβ travelling with a speed of 90 km/h can
cross a pole in 20 seconds. If the length of train βBβ is 60% less than that of train βAβ and it can cross a pole in 16 seconds then speed (in km/h) of train βBβ is:Solution
Speed of train βAβ = 90 Γ (5/18) = (25) m/s Length of train βAβ = (25) Γ 20 = 500 metres Length of train βBβ = 0.4 Γ 500 = 200 metres Speed of train βBβ = (200/16) Γ (18/5) = 45 km/h
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