Question
Train ‘A’ travelling with a speed of 90 km/h can
cross a pole in 20 seconds. If the length of train ‘B’ is 60% less than that of train ‘A’ and it can cross a pole in 16 seconds then speed (in km/h) of train ‘B’ is:Solution
Speed of train ‘A’ = 90 × (5/18) = (25) m/s Length of train ‘A’ = (25) × 20 = 500 metres Length of train ‘B’ = 0.4 × 500 = 200 metres Speed of train ‘B’ = (200/16) × (18/5) = 45 km/h
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