Question
In a 2000-metre race, 'Aarav' beats 'Dev' by '400'
metres and 'Ishaan' by '600' metres. If 'Dev' and 'Ishaan' participate in an 800-metre race, and 'Ishaan' gets a head start of 80 metres, then find the distance between 'Dev' and 'Ishaan' when the winner reaches the finish line.Solution
ATQ, Ratio of speeds of 'Aarav', 'Dev', and 'Ishaan' = 2000 : (2000 - 400) : (2000 - 600) = 10 : 8 : 7 So, ratio of speeds of Dev and Ishaan = 8 : 7 Distance covered by 'Ishaan' in the time taken by 'Dev' to cover 800 metres = 800 × (7/8) = 700 metres Total difference between 'Dev' and 'Ishaan' when 'Dev' reaches the finish line = 800 - (700 + 80) = 20 metres So, 'Dev' will beat 'Ishaan' by 20 metres.
[(√576 × √144) ÷ √1296]2 = ? ÷ 3
Evaluate:
(24/6) + 3 × (5 - 2)2
What will come in the place of question mark (?) in the given expression?
{(16 × 25) ÷ 32} × 12 = ? – 200
Find the value of 40 ÷ 5 of 6 × [3 ÷ 6 × (12 – 6)] – (15 ÷ 3 of 30):
Calculate the value of x2, if [(8 + 62) ÷ 4 of x + 2.5 × 5 = 42 + 20% of 10].
- What will come in place of (?), in the given expression.
144 ÷ √36 + 13² – 100 = ? √? = 120 - 102 + ∛125
360 ÷ 9 + 15 % of 200 + ? * 10 = 45 * √25
- Determine the value of following expression:
[{(148 + 32) ÷ 9}% x 1350] + 19 280 – 70 × 14 ÷ 5 = ? – 21 of 3
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