Question
In a 2000-metre race, 'Aarav' beats 'Dev' by '400'
metres and 'Ishaan' by '600' metres. If 'Dev' and 'Ishaan' participate in an 800-metre race, and 'Ishaan' gets a head start of 80 metres, then find the distance between 'Dev' and 'Ishaan' when the winner reaches the finish line.Solution
ATQ, Ratio of speeds of 'Aarav', 'Dev', and 'Ishaan' = 2000 : (2000 - 400) : (2000 - 600) = 10 : 8 : 7 So, ratio of speeds of Dev and Ishaan = 8 : 7 Distance covered by 'Ishaan' in the time taken by 'Dev' to cover 800 metres = 800 × (7/8) = 700 metres Total difference between 'Dev' and 'Ishaan' when 'Dev' reaches the finish line = 800 - (700 + 80) = 20 metres So, 'Dev' will beat 'Ishaan' by 20 metres.
`sqrt(1297)` + 189.99 =?
90.004% of 9500 + 362 = ?
(74.76 ÷ 12.11 X ?)% of 239.89 = 600.19
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
1784.04 - 483.98 + 464.98 ÷ 15.06 = ?3
If tan θ + cot θ = 16, then find the value of tan2θ + cot2θ.
480 ÷ 10 + 18 % of 160 + ? * 9 = 60 * √36
(95.89% of 625.15 + 36.36% of 499.89) ÷ 6.02 = ? – 269.72
11.89 × 2.10 × 4.98 × 4.03 ÷ 7.98 of 15.03 = ?
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