Question
A man travels a specific distance at a given speed,
completing the journey in a set amount of time. If he had reduced his speed by 10 km/h, it would have taken him an additional 2 hours to cover the same distance. Further, if he had decreased his speed by another 10 km/h (a total reduction of 20 km/h from the original speed), the journey would have taken an additional 3 hours beyond the initial 2-hour delay. Determine the total distance he traveled.Solution
Let, distance be ‘d’ km So, d/(s – 10) – d/s = 2 Or, 10d = 2s(s – 10) Or, d = 2 × s(s – 10)/10 -----(i) And, d/(s – 20) – d/s = 5 Or, 20d = 5 × s(s – 20) Or, d = 5 × s(s – 20)/20 --------(ii) From (i) and (ii), Let S1 = 10 km/h S2 = 20 km/h T1 = 2 hours T2 = 5 hours Let original speed be S km/h [(S – 10) × 2]/10 = [(S – 20) × 5]/20 4(S – 10) = 5(S – 20) 4S – 40 = 5S – 100 S = 60 km/h Required distance = 60 × (60 – 10)/10 × 2 = 60 × 5 × 2 = 600 km
In the isothermal Process ______________ remains Constant.
Who defined the law of gravitation?
‘Therm' is the unit of –
What type of image is always formed by a convex mirror?
Quantum Theory was discovered by
If an object starts moving and if there is no friction at all, what happens?
Which of the following is a vector quantity?
Vivek was walking in the park. On the way he found a stone lying. He picked the stone and threw it up in the sky. After few seconds, he observed that th...
Which of the following instruments is used to measure humidity?
For a wave, wavelength divided by the time period equals ________.
Relevant for Exams:
