Question
A man travels a specific distance at a given speed,
completing the journey in a set amount of time. If he had reduced his speed by 10 km/h, it would have taken him an additional 2 hours to cover the same distance. Further, if he had decreased his speed by another 10 km/h (a total reduction of 20 km/h from the original speed), the journey would have taken an additional 3 hours beyond the initial 2-hour delay. Determine the total distance he traveled.Solution
Let, distance be ‘d’ km So, d/(s – 10) – d/s = 2 Or, 10d = 2s(s – 10) Or, d = 2 × s(s – 10)/10 -----(i) And, d/(s – 20) – d/s = 5 Or, 20d = 5 × s(s – 20) Or, d = 5 × s(s – 20)/20 --------(ii) From (i) and (ii), Let S1 = 10 km/h S2 = 20 km/h T1 = 2 hours T2 = 5 hours Let original speed be S km/h [(S – 10) × 2]/10 = [(S – 20) × 5]/20 4(S – 10) = 5(S – 20) 4S – 40 = 5S – 100 S = 60 km/h Required distance = 60 × (60 – 10)/10 × 2 = 60 × 5 × 2 = 600 km
A series is 48, 129, 298, 587, 1028, 1653
If another series 150, ___, m, ___, follows the same pattern as the given number series, then find th...
35 36 68 207 836 4205
...15 13 28 24 54 52
...114 106 102 100 99 ?
...12, 24, 72, 288, 1440, ?
13, 14, 18, 27, 43, ?
20 25 54 165 662 ?
...6 5 40 32 249 240
92, 51, 21, 13.5, x, 4.25
find the value of (10x + x -5)?
3 25 173 1041 5201 20809
10 a �...