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    Question

    Two trains depart from the same station. The first train

    departs at 8:00 A.M., traveling at a speed of 60 km/h. Two hours later, at 10:00 A.M., the second train leaves the station, traveling at a faster speed of 72 km/h. At what time will the second train catch up to the first train?
    A 6:00 P.M. Correct Answer Incorrect Answer
    B 8:00 P.M. Correct Answer Incorrect Answer
    C 10:00 P.M. Correct Answer Incorrect Answer
    D 11:30 P.M. Correct Answer Incorrect Answer
    E 12:30 A.M. Correct Answer Incorrect Answer

    Solution

    We can see that the first train leaves 2 hours before the second train. So, distance travelled in 2 hours by the first train = 2 X 60 = 120 km So, time taken by the two trains to meet = 120 ÷ (72 - 60) = 10 hours So, the second train will meet the first train at 10:00 AM + 10 hours = 8:00 P.M.

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