Start learning 50% faster. Sign in now
Let the usual speed of the train be x km/hr. Usual time = Distance / Speed = 180/x hr If the speed is increased by 2 km/hr, that is (x + 2) km/hr. The new time is = 180/(x+z) hr 180/x - 180/(x+z) = 3 180x + 360 -180 = x (3x + 6) x (3x + 6) = 360 x(x+2) = 120 x ² + 2x = 120 x ² + 2x - 120 = 0 x = 10, x = -12 Therefore, usual speed of the passenger train is 10 km/hr.
Alternate method: Let speed of train is x kmph. Distance = (Gap of time× Product of speed ) / (Gap of Speed) 180 = (3hrs× x× (x+2)) /2 360 = 3hrs× x× (x+2) 120 = x× (x+2) So x = 10 kmph
Which of the following are major activities undertaken by the Central Ground Water Board (CGWB) under the Ground Water Management and Regulation (GWMR) ...
In which of the following Indian states does the southwest monsoon set first to give rainfall?
The dress of Rajasthani 'Tara Bhant ki Odhni' is popular in -
Which Union Territory’s appropriation Bill passed in Lok Sabha in 2021 allowed the Central Government to authorise payment and appropriation of certai...
What do you call a person who speaks more than one language?
Which organization is responsible for regulating the stock market in India?
What does the acronym PM PRANAM stand for in the context of the Union government's scheme aimed at reducing the use of chemical fertilisers and reducing...
Which of these private financial institutions have raised Rs 3595 crore via Infrastructure Bonds ?
What is a prominent trend in the microfinance sector in India?
Who has been appointed as the Chief Election Commissioner of the Election Commission of India (ECI) with effect from 15 May 2022?