Question
How far will 'Raj' travel by the time he catches up to
'Amit', given that 'Raj' starts 120 km behind and moves at 50 km/h while 'Amit' moves at 40 km/h?Solution
ATQ,
Relative speed of 'Raj' w.r.t 'Amit' = 50 - 40 = 10 km/h
Time taken by 'Raj' to overtake 'Amit' = (120/10) = 12 hours
So, distance covered by 'Raj' in 12 hours = 50 Ć 12 = 600 km
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