Question
How far will 'Raj' travel by the time he catches up to
'Amit', given that 'Raj' starts 120 km behind and moves at 50 km/h while 'Amit' moves at 40 km/h?Solution
ATQ,
Relative speed of 'Raj' w.r.t 'Amit' = 50 - 40 = 10 km/h
Time taken by 'Raj' to overtake 'Amit' = (120/10) = 12 hours
So, distance covered by 'Raj' in 12 hours = 50 × 12 = 600 km
(14.14 × 29.98) + 20.15% of 549.99 = ? + 120.34
? = 44.78% of 839.91 – 48.12% of 774.89 + 55.77% of 1024.85
79.95 × 25.001 – 20.001 × 129.90 + 839.99 = ?
24.45% of 14.99% of 14999.78 + 159.80 = ?% of 1999.78
(2100.23 ÷ 34.98) + (864.32 ÷ 23.9) + 1854.11 =?
1959.09 + 33.94% of 6250.06 – ? = √10609.02 + √144.24
15.232 + 19.98% of 649.99 = ? × 4.99
149.78% of 319.87 – 199.83% of 45.45 = 130.03% of (? × 12.01)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
