Question
Before servicing, a car runs at a speed of 28 km/hr
while after servicing, it runs at a speed of 56 km/h. After servicing the car covers a certain distance in 7 hours. How much time would the car have taken to cover the same distance when it was not serviced?Solution
After servicing, Distance covered by the car = 56 × 7 = 392 km Required time taken = 392/28 = 14 hours
The HCF of a^6 - 1 and a^4+ 2a^3- 2a-1 is
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The ratio of two numbers is 5:10 and their LCM is 100. The numbers are:
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