Question
A man leaves point 'C' at 6:00 AM walking at 6 km/h. A
scooter starts from 'C' at 8:00 AM and travels in the same direction at 36 km/h. When will the scooter overtake the man?Solution
ATQ,
Distance between man and scooter when scooter starts = 6 × 2 = 12 km
Relative speed = 36 − 6 = 30 km/h
Time taken by scooter to overtake = 12 / 30 = 0.4 hours = 24 minutes
Required time = 8:00 AM + 24 minutes = 8:24 AM
More Time and distance Questions
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1540 ÷ 7 - 184 ÷ 8 = ?
{(81% of 800 + 28 × 4) – 27 × ?} = 11 × 20
? ÷ 62 × 12 = 264
- Evaluate: 156 ÷ 12 × 4 + 180 – 40% of 350
25% of 1000 + 10% of 150 – 22 × ? = 45
- Find the simplified value of the given expression.
672 ÷ 28 × 24 + 363 – 309 =?
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