Question
A man leaves point 'C' at 6:00 AM walking at 6 km/h. A
scooter starts from 'C' at 8:00 AM and travels in the same direction at 36 km/h. When will the scooter overtake the man?Solution
ATQ,
Distance between man and scooter when scooter starts = 6 × 2 = 12 km
Relative speed = 36 − 6 = 30 km/h
Time taken by scooter to overtake = 12 / 30 = 0.4 hours = 24 minutes
Required time = 8:00 AM + 24 minutes = 8:24 AM
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