Question
βAβ and βBβ started moving towards each other at
same time with a speed of 27 km/hr and 15 km/hr, respectively. If the distance covered by βAβ is 36 km more than that by βBβ, when they meet then find the initial distance between them.Solution
Difference in speed = 27 - 15 = 12 km/hr Time taken = 36/12 = 3hrs Required distance = travelled distance by A + travelled distance by B = 27 Γ 3 + 15 Γ 3 = 81 + 45 = 126 km
More Time and distance Questions
(480 + 340 - ?) Γ (3/19) = 90Β
- What will come in place of the question mark (?) in the following questions?
0.5Γ120+25=? 1.55 + 2.05 + 1.5 × 11 – 20% of 10.5 = ?
What will come in place of the question mark (?) in the following expression?
?% of 600 + 15 Γ 28 = 30% of 1800
β324 + β484 + 63 = ?2Β
240 Γ 2.5 + 65 Γ 2/13 = ?2 - β225
Find the value of βyβ if (2/7) Γ y = 0.79 β 1.77 Γ· 3.
20 * 8 + 40% of 100 + 60% of 150 = ?
325934.78 + 78545.30 + 92.25 =?
- What will come in the place of question mark (?) in the given expression?