Question
A taxi traveled from point P to
point Q without stopping. It covered the first 64 km of the journey at a speed of 32 km per hour. The second part of the journey was 150% longer than the first part and was traveled at a speed of 50 km per hour. Given that the overall average speed for the entire trip was 40 km per hour, what is the approximate average speed for the remaining 76 km?Solution
ATQ, First travel time = 64/32 = 2 hours Remaining distance = 64×250/100 = 160 Total distance = 64+ 160 + 76 = 300 km Total time taken = 300/40 = 7.5 hours Time taken for 160 miles = 160/50 = 3.2 hours Remaining time = 7.5 - 2 - 3.2 = 2.3 Required average speed = 76/2.3 = 33 kmph
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Statements: J = S ≤ A = Y > X, W ≥ J > O = B
Conclusion:
I. W ≥ S
II. S > B
III. B < A
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Statement:
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Conclusion :
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