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Let the total distance covered by ‘A’ be ‘4x’ km Distance covered with speed of 15 km/hr = 0.5 × 4x = 2x km/hr Distance covered with speed of 5 km/hr = 0.5 × (4x – 2x) = ‘x’ km/hr ATQ, (2x/15) + (x/5) + (x/3) = 10 Or, {(2x + 3x + 5x)/15} = 10 Or, 10x = 150 Or, x = 150/10 = 15 Therefore, total distance covered by ‘A’ = 4x = 60 km
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