Question
A train takes 22 seconds to pass a tunnel of length 500 m
and also overtakes a cyclist riding at 8 m/s in the opposite direction in 7 seconds. Determine the train's speed.Solution
ATQ,
Speed of the train = x m/s
Length of the train = y m
x = (y + 500)/22 ---- (1)
x + 8 = y/7
7x + 56 = y ---- (2)
Substitute (2) in (1)
x = (7x + 56 + 500)/22
22x = 7x + 556
x = 37
Speed of the train = 37 m/s
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