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Let the length of the slower and Faster train be x and yrespectively Now relative speed of train when travelling opposite direction = 75 + 60 = 135 km/hr = 135 × (5/18)m/s= 37.5 m/s Now distance covered (x) = 37.5 × 12 = 450 m ......................... (i) When travelling in same direction, relative speed = 75 – 60 = 15 km/hr = 15 × (5/18)m/s= 75/18 m/s As the time noted by the person in the faster is 90 seconds, the distance covered will be equal to the length of slower train Distance covered (y) = 75/18 × 90 = 375m ................................... (ii) From (i) and (ii) we get x= 75m
130 136 148 166 ? 232
5 10 30 150 950 11550
...1 5 36 343 ? 59049
...Three series are provided below. You need to determine the values of A, B, and C and subsequently establish a relationship among them.
I: 4, 10...
? 190 210 238 274 318
...35.25 71 146 296 624 1376
...5 10 40 80 320 640
4 a b c d e
Find the value of d.
...Find the 31st term of the series 25, 29, 33……
Direction: Which of the following will replace ‘?’ in the given question?
10, 12, ‘?’, 27, 36, 45, 54, 63, 72
30 27 20 9 ? - 25