Let the length of the slower and Faster train be x and yrespectively Now relative speed of train when travelling opposite direction = 75 + 60 = 135 km/hr = 135 × (5/18)m/s= 37.5 m/s Now distance covered (x) = 37.5 × 12 = 450 m ......................... (i) When travelling in same direction, relative speed = 75 – 60 = 15 km/hr = 15 × (5/18)m/s= 75/18 m/s As the time noted by the person in the faster is 90 seconds, the distance covered will be equal to the length of slower train Distance covered (y) = 75/18 × 90 = 375m ................................... (ii) From (i) and (ii) we get x= 75m
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