Question
Train A and train B cross a pole in 8 sec and 9 sec
respectively. Train A can cross a platform in 18 sec and train B can cross the same platform in 24 sec. The length of the platform is 300 metre. Find the difference of the lengths of trains A and B.Solution
ATQ,
Let length of Train A = LA Crosses pole in 8 sec → speed = LA / 8 Crosses 300 m platform in 18 sec → (LA + 300) = (LA / 8) × 18 LA + 300 = (9LA)/4 4LA + 1200 = 9LA → 5LA = 1200 → LA = 240 Let length of Train B = LB Crosses pole in 9 sec → speed = LB / 9 Crosses 300 m platform in 24 sec → (LB + 300) = (LB / 9) × 24 LB + 300 = (8LB)/3 3LB + 900 = 8LB → 5LB = 900 → LB = 180 Hence, required difference = 240 – 180 = 60 meters
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