Question
Train A and train B cross a pole in 8 sec and 9 sec
respectively. Train A can cross a platform in 18 sec and train B can cross the same platform in 24 sec. The length of the platform is 300 metre. Find the difference of the lengths of trains A and B.Solution
ATQ,
Let length of Train A = LA Crosses pole in 8 sec β speed = LA / 8 Crosses 300 m platform in 18 sec β (LA + 300) = (LA / 8) Γ 18 LA + 300 = (9LA)/4 4LA + 1200 = 9LA β 5LA = 1200 β LA = 240 Let length of Train B = LB Crosses pole in 9 sec β speed = LB / 9 Crosses 300 m platform in 24 sec β (LB + 300) = (LB / 9) Γ 24 LB + 300 = (8LB)/3 3LB + 900 = 8LB β 5LB = 900 β LB = 180 Hence, required difference = 240 β 180 = 60 meters
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