Question
Train A running at a speed of 48 km/hr crosses train B
in 20 seconds. Find the speed of train B (in km/hr), if the sum of the length of train A and B is 450 meters and both trains running in the opposite direction.Solution
Let speed of train B be ‘x’ km/hr. According to question, => 20(48 + x) × (5/18) = 450 => 960 + 20x = 1620 => 20x = 660 => x = 33 km/hr
More Trains Questions
(400.01% of 149.89) ÷ 49.97 = ?2 ÷ (95.98 ÷ 31.99)Â
`11(2/13)` + `5(2/11)` - `3(4/9)` = ?
What approximate value will replace the question mark (?) in the following?
29.99...
(4913)1/3  × 10.11 × 13.97 ÷ 20.32 = ? + 39.022
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
120.02% of 599.90 + (34.78/20.89) × (47.98) = ?2 – 10.022
6.992 + (2.01 × 2.98) + ? = 175.03
509.85 ÷ 15.05 + 210.16 – 18.06 × 5.95 = ?
124.88% of 60.101 + 18.09% of 849.87 – 22.12% of 1049.93= ? – 19.93
