Question
A 160 m long train crosses another 320 m long train
running in the opposite direction in 12 seconds. If the shorter train crosses a pole in 16 seconds, what is the speed of longer train?Solution
Speed of the shorter train = 160/16 = 10 m/sec Let the speed of the longer train be x km/hr According to the question, ⇒ (10 + x) = (160 + 320)/12 ⇒ 10 + x = 480/12 ⇒ x = 40 – 10 = 30 ⇒ x = 30 x 18/5 = 108 km/hr
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