Question
Two trains are running on parallel lines in the same
direction at the speed of 76 km/h and 40 km/h respectively. The faster train crosses a man in the slower train in 55 second. If the length of the slower train is 7/11th of the faster train, then find the length of the slower train.Solution
According to the question, => (76 – 40) × (5/18) = D/55 => D = 550 m Length of the faster train = 550 m Length of the slower train = 550 × (7/11) = 350 m
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