Question
Train βAβ running with a speed of 126 km/hr can
cross a standing goods train of 6 times its length in 30 seconds. Find the time taken by 200 metres long train βBβ which is coming from opposite direction of train βAβ, with a speed of 20 m/s, to cross train βAβ.Solution
Let the length of train βAβ be βxβ metres Therefore, length of the goods train = β6xβ metres Speed of train βAβ = 126 Γ (5/18) = 35 m/s According to the question, 6x + x = 35 Γ 30 => 7x = 1050 => x = 150 Therefore, time taken by train βBβ to cross train βAβ = {(150 + 200)/(30 + 20)} = 7 seconds
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