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The ratio between the speeds of train J and K is 7:5 respectively. Let’s assume the speed of train J and K is 7y and 5y respectively. Train J which is (a+140) metre long can cross a pole in 24 seconds. (a+140)/24 = 7y (a+140) = 168y Eq.(i) If train K can cross a man in 28 seconds. Let’s assume the length of train K is ‘k’. k/5y = 28 k = 140y Eq.(ii) It is assumed that both of the trains cross each other in (77/3) seconds. [(a+140)+k]/(7y+5y) = (77/3) [(a+140)+k]/(12y) = (77/3) Put Eq.(i) and Eq.(ii) in the above equation. [168y+140y]/(12y) = (77/3) (308y)/(12y) = (77/3) (77/3) = (77/3) We cannot obtain anything from the given information in the question. So the answer cannot be determined.
Suppose xy = -15 and (x² + y²) = 34, then determine the value of (x – y).
when x =4 and y =-6 then find the value of 27x³ +58x²y +31xy² +8y³?
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Find the number in place of ?
6, 14, 26, ?, 106, 214
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(a+2 )² + (b-5)² + (c+3)² = 0
Find the value of√ (a + b + c)?
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