Question
A train crosses a signal post in 36 seconds and a tunnel
of length 360 metres in 66 seconds. What is the train’s speed in km/h?Solution
ATQ,
Let the speed of train be 'v' m/s Length of train = 36v metres So, (36v + 360) ÷ 66 = v ⇒ 36v + 360 = 66v ⇒ 30v = 360 ⇒ v = 12 Speed of train = 12 m/s = 12 × (18/5) = 43.2 km/h
Nonplussed
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