Question
A train of length ‘x’ meters crosses a stationary
man in 8 seconds. It also crosses a bridge of length ‘x + 150’ meters in 22 seconds. What is the value of ‘x’?Solution
Speed of train = x/8 m/s So, (x + x + 150)/22 = x/8 => (2x + 150)/22 = x/8 => 8(2x + 150) = 22x => 16x + 1200 = 22x => 6x = 1200 => x = 1200 / 6 => x = 200 m
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