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    Question

    A train of length ‘x’ meters crosses a stationary

    man in 8 seconds. It also crosses a bridge of length ‘x + 150’ meters in 22 seconds. What is the value of ‘x’?
    A 225 m Correct Answer Incorrect Answer
    B 175 m Correct Answer Incorrect Answer
    C 200 m Correct Answer Incorrect Answer
    D 195 m Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Speed of train = x/8 m/s So, (x + x + 150)/22 = x/8 => (2x + 150)/22 = x/8 => 8(2x + 150) = 22x => 16x + 1200 = 22x => 6x = 1200 => x = 1200 / 6 => x = 200 m

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