Question
Aβ and βBβ together can complete a work in 10
days, while βBβ and βCβ together can complete the work in 20 days. If βBβ takes 8 days to complete the work alone then find the time taken by all three together to complete 57.5% of work.Solution
Let the total work = 40 units Efficiency of (A + B) = 40/10 = 4 units/day Efficiency of (B + C) = 40/20 = 2 units/day Efficiency of βBβ = 40/8 = 5 units/day Efficiency of (A + B + C) = (4 + 2 β 5) = 1 units/day Required time taken = (0.575 Γ 40)/1 = 23 days
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