Question
A and B alone can complete a work in 30 and 60 days,
respectively. 50% of the work is completed by C in 6x days, and the remaining work is completed by A and B working together in ‘x’ days. Find the time taken by B and C to complete the whole work while working together.Solution
Time taken by A and B to complete the whole work while working together = (30 × 60)/(30 + 60) = 20 days So, x = 20/2 = 10 (Since, 50% of the work is done by A and B together) As, time taken by C to complete 50% of the work = 10 × 6 = 60 days So, time taken by C to complete the entire work = 60 × 2 = 120 days Therefore, time taken by B and C to complete the whole work while working together = (120 × 60)/(120 + 60) = 40 days
What will come in the place of question mark (?) in the given expression?
?% of 2480 + 15 × 34 = 1440
(82 + 62 ) × 1.25 + 20% of 145 = ? – 40% of 65Â
Evaluate: (768÷16)×(125÷25)−(81÷9)×12
What will come in place of (?) in the given expression.
40% of (120 + 80) + 25% of 160 = ?What value should come in the place of (?) in the following questions?
(3√1728 * 25) ÷ 3 * ? = 250 + 50* 3
What will come in the place of question mark (?) in the given expression?
65% of 900 - 45% of 600 = ? X 3Â
- What will come in the place of question mark (?) in the given expression?
?² = 28% of 35% of 4500 Simplify the expression:
(9x² - 25) / (3x + 5)
[{(3 × 54 × 21)/63} + 6] / 6 = √?Â
3.2% of 500 × 2.4% of ? = 288
