Question
3 men dig a hole in 10 days. How many days would it take
for 5 men to dig the same hole ?Solution
(M1 x D1)/W1 = (M2 x D2)/W2 (3 x 10)/1 = (5 x D)/1 D = 6 days
(γ(0.5)γ^(1/3)Β Γ γ(1/125)γ^(1/4)Β Γ γ25γ^(1/6)Β Γγ(6.25)γ^(2/3))/(γ(2.5)γ^(2/3)Β Γ 5^(-1/2)Β Γ γ(1/5)γ^(-2)Γγ3125οΏ½...
?2 - (40% of 240) = 25 X 5
β157464 =?
32 + 26 Γ (484 Γ· 44) + 450 Γ· 9 = ?Β
(1748 ÷ 8) + 76.8 × 35 =(? × 4) + (42 × 35.5)
52% of 36% of 810 = 72% of 18% of ?Β
Find the simplified of the following expression:
Solve:
5(x - 2) = 3(x + 4) + 4
18 * 9 + 25% of 120 + 50% of 200 = ?
756 + 432 β 361 + ? = 990