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Start learning 50% faster. Sign in nowP, Q and R can do a piece of work in 10, 20 and 30 days respectively. Total work = 60 (LCM of 10, 20 and 30) P's efficiency = 60/10 = 6 Q's efficiency = 60/20 = 3 R's efficiency = 60/30 = 2 Pattern of work = PQ, PR, PQ, PR... Work done by PQ and PR in 2 days = (6 + 3) + (6 + 2) = 17 2 days => 17 units 2 × 3 = 6 days => 17 × 3 = 51 units remaining 9 units done by PQ in = work/efficiency = 9/(6 + 3) = 1 day Total time taken = 6 + 1 = 7 days ∴ P, Q and R complete the work together when P is assisted by Q and R on every alternate day in 7 days.
Amit and Bheem can individually finish a task in 10 days and 15 days, respectively. If they work together to complete the task an...
116.90 ÷ (77.81 ÷ 6.06) + 6.32 = (15.12% of ?) ÷ 4.652
14.12 × 21.98 + 25.22% of 195.99 = ? × 50.9
45.22% of (71.9 x 5.01) + 69.97 =?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Find the value of ‘x’ in the given expression:[144 + {2 × (13 ÷ 0.5 × 6 – 3) ÷ 4} – 6.5] = x
1587.9 + 9650.98 + 10612.8 =?3 - 2536.67
65.22 of 359.98% + 459.99 ÷ 23.18 = ?
(1560.23 ÷ 25.98) + (768.32 ÷ 23.9) + 1814.11 = ?