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P, Q and R can do a piece of work in 10, 20 and 30 days respectively. Total work = 60 (LCM of 10, 20 and 30) P's efficiency = 60/10 = 6 Q's efficiency = 60/20 = 3 R's efficiency = 60/30 = 2 Pattern of work = PQ, PR, PQ, PR... Work done by PQ and PR in 2 days = (6 + 3) + (6 + 2) = 17 2 days => 17 units 2 × 3 = 6 days => 17 × 3 = 51 units remaining 9 units done by PQ in = work/efficiency = 9/(6 + 3) = 1 day Total time taken = 6 + 1 = 7 days ∴ P, Q and R complete the work together when P is assisted by Q and R on every alternate day in 7 days.
79.99% of (84.89 × 5.99) - (3.89)2 × 21.87 = ?
2 (1/4)% of 7999.78 + {49.77% of 899.71} + √144.14 - 20% of 1499.83 = ?
?% of 1200.22 + 319.82 = 3.99 × 295.64
45.22% of (71.9 x 5.01) + 69.97 =?
15.001% of 799.99 - 3/11% of 1099.99 + 111.002 = ?
(74.76 ÷ 12.11 X ?)% of 239.89 = 600.19
The speed of the boat in still water is 20% less than the speed of the boat in downstream. The time taken by the boat to cover 780 km distance in upstre...
(44/25) ÷ (154/199.5) × 419.91 = ? – (11.11)3
(2310.23 ÷ 32.98) + (1008.32 ÷ 23.9) + 1594.11 = ?