Question
A can do (2/5) of a work in 6 days and B can do 30% of
the same work in 3 days. They worked together for 4 days. The remaining work was completed by C alone in 6 days. B and C together can complete 70% of the original work in:Solution
A can complete the whole work in 6 × 5/2 = 15 days B can complete the whole work in 3 × 100/30 = 10 days Let the total unit of work be 30 unit (LCM of 15 and 10) Efficiency of A = 30/15 = 2 unit/day Efficiency of B = 30/10 = 3 unit/day Work done by A and B in 4 days = (2 + 3) x 4 = 20 unit Remaining work = 30 - 20 = 10 units Let the remaining work completed by C in x days 6 x x = 10 x = 10/6 B and C together can complete 70% of the original work in 30/(3 + 10/6) x 70/100 = 4 (1/2) days
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
Find the value of ‘x’ in the given expression:[144 + {2 × (13 ÷ 0.5 × 6 – 3) ÷ 4} – 6.5] = x
41.97 × 5.12 ÷ 2.99 + 49.89 = ?× 1.99
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
49.96% of 861.34 + 2250% of 55.12 = ?
23.95% of 274.99 - 34.99% of 120.01 = 19.95% of ?
√1567.763`xx` √4400 ÷ 326.9827 + 1223.293 = ?
Rice at Rs 80/kg is mixed with rice at Rs.40/ kg in a certain ratio such that by selling the mixture at Rs.60/ kg profit of 20% is made. If the quantity...
647.1 ÷ ? + 72.3 × 209.81 – 8743.1 = 6404
11.992 + (6.01 × 5.98) + ? = 350.03
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