Question
A can complete a work in 10 days, B in 15 days and C in
30 days. All three work together for 2 days. Then B leaves. In how many more days will A and C finish the remaining work?Solution
A's 1 day work = 1/10 B's 1 day work = 1/15 C's 1 day work = 1/30 Together in 1 day: 1/10 + 1/15 + 1/30 = 3/30 + 2/30 + 1/30 = 6/30 = 1/5 Work done in 2 days = 2/5 Remaining work = 1 - 2/5 = 3/5 Now A and C work together: 1/10 + 1/30 = 3/30 + 1/30 = 4/30 = 2/15 Time taken = (3/5) / (2/15) = 3/5 x 15/2 = 9/2 = 4 1/2 days
What is the simplified value of the given expression?
4(sin² 20° + sin² 70°) + 2sin 30° - (2sec 60° + cot 45°)
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