Question
A, B and C can complete a work in 10, 20 and 15 days
respectively. A left the work 3 days before the work was completed and B left 1 days after A had left. The number of days required to complete the whole work is:Solution
A’s one day work = 1/10 B’s one day work = 1/20 C’s one day work = 1/15 Let total units of work be = 60 Efficiency of (A) = 6 Efficiency of (B) = 3 Efficiency of (C) = 4 Let ‘x’ days are required to complete the whole work. => 4x + 6(x-3) + 3(x-2) = 60 => 4x + 6x – 18 + 3x – 6 = 60 => 13x = 84 => x = 84/13 days
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