Question
A can complete a work in 9 days , and B can complete
it in 18 days . They work together with C and complete the work in 3 days . In how many days can C alone  complete the work?Solution
Assume total work = LCM(9, 18) = 18 units A’s rate = 18/9 = 2 units/day B’s rate = 18/18 = 1 unit/day Let C’s rate = x units/day Total rate = (2 + 1 + x) units/day = (3 + x) They finish in 3 days: (3 + x) × 3 = 18 9 + 3x = 18 3x = 9 → x = 3 units/day Time for C alone = 18 / 3 = 6 days
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