Question
'X' and 'Y' together can complete the work in 24 days. 'Y' alone can complete the work in 40 days. If Z is 33.33% more efficient than X, find the time taken by 'Z' alone to finish the work.
Solution
Let the total work be 240 units Combined efficiency of 'X' and 'Y' = (240/24) = 10 units/day Efficiency of 'Y' alone = (240/40) = 6 units/day Efficiency of 'X' alone = 10 - 6 = 4 units/day Efficiency of 'Z' = 4 X (4/3) = (16/3) units/day Time taken by 'Z' alone to finish the work = 240 ÷ (16/3) = (240 X 3)/16 = 45 days
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