Question
A can complete a piece of work in 24 days. He worked for
21 days and then B finished the remaining work in 6 days. In how many days can A and B finish the work together?Solution
A can complete a piece of work in 24 days. A does the work in 24 days =1 A does the work in 1 day =1/24 A does the work in 21 days = (1/24) ×21=7/8 Remaining work =1-7/8 =1/8 Remaining work finished by B in 6 days =6×8=48days. A and B together finish the work – 2448 96 42 =96/4+2 =96/6 =16 days.
More Time and work Questions
2350 – 4830 + 9570 + 3350 – 1720 = ?
40% of 1820 + 80% of 630 = 90% of 1280 + ?
What is (0.08% of 0.008% of 8)1/9 ?
18, 25, 33, 42, 52, 63, ?
If 1560 ÷ 30 + 2025 ÷ 45 - z + 33 × 7 = 1848 ÷ 24 × 234 ÷ 39, then the value of z is:
44% of 1250 + 46 × 34 = 40% of ? + 1154
12.5% of 384 - 16.66% of 66 = √16 + √? + 22
9 × 40 × 242 × 182 = ?2
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