Question
There is enough food in a camp to last for 40 days if
each of the 50 soldiers present at the camp eat 3 times a day. After 10 days, 25 more soldiers joined the camp and remaining ate only twice a day. For how many days (from start) will the food last?Solution
Let the eating capacity of each soldier be 'x' units So, total food at the camp = (40 X 50 X 3 X x) = '6000x' units And food remaining after 10 days = 6000x - (10 X 50 X 3 X x) = '4500x' units So, required time = 4500x ÷ (x X 2 X 75) = 30 days So, the food will last for a total of 30 + 10 = 40 days
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