Question
βMβ and βNβ together can finish a piece of work
in 22 days. If βMβ alone can complete it in 55 days, how many days will βNβ alone take?Solution
Let the total work be LCM (22, 55) = 110 units.
Combined efficiency of βMβ and βNβ = 110 Γ· 22 = 5 units/day
Efficiency of βMβ = 110 Γ· 55 = 2 units/day
Efficiency of βNβ = 5 β 2 = 3 units/day
Time taken by βNβ alone = 110 Γ· 3 = (110/3) days
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