Question
Person A is twice as efficient as Person B. Person B can
complete a certain task in 32 days, while Person C takes 4 days more than Person A to finish the same task. Which of the following could be the number of days they work together such that the task remains incomplete?Solution
According to the question,
Time taken by ‘A’ to complete the work = 32/2 = 16 days
Time taken by ‘C’ to complete the work = 16 + 4 = 20 days
Let the total work = 160 units
Efficiency of ‘A’ = 160/16 = 10 units/day
Efficiency of ‘B’ = 160/32 = 5 units/day
Efficiency of ‘C’ = 160/20 = 8 units/day
When they work together for 7 days, work done = (10 + 5 + 8) × 7 = 161 units
Therefore, maximum number of days they can work together such that the work doesn’t get completed is 6 days.
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