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    Question

    A, B, and C together wrap up a task in 14 days. B and C

    together can finish it in (280/18) days, and C alone completes half in 14 days. Find the ratio of the efficiency of A to B.
    A 5:4 Correct Answer Incorrect Answer
    B 1:4 Correct Answer Incorrect Answer
    C 2:3 Correct Answer Incorrect Answer
    D 7:5 Correct Answer Incorrect Answer

    Solution

    1/A + 1/B + 1/C = 1/14 C alone complete the whole work = 14 × 2 = 28 days B and C together = (280/18) days ⇒ rate = 18/280 = 9/140 1/A = 1/14 – 9/140 = (10 – 9)/140 = 1/140 1/B = 9/140 – 1/28 = (9 – 5)/140 = 4/140 = 1/35 A alone complete the work = 140 days B alone complete the work = 35 days Required ratio = (1/140) : (1/35) = 1 : 4

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