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      Question

      β€˜R’ alone can build a wall in 40 days. Together,

      β€˜R’ and β€˜S’ can do it in 25 days. If β€˜S’ worked for 8 days alone and stopped, how many more days would β€˜R’ need to complete the task?
      A 20 days Correct Answer Incorrect Answer
      B 18 days Correct Answer Incorrect Answer
      C 12 days Correct Answer Incorrect Answer
      D 10 days Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let total work = 200 {L.C.M of 40 and 25}

      Efficiency of β€˜R’ = 200 Γ· 40 = 5 units/day

      Combined efficiency of β€˜R’ and β€˜S’ = 200 Γ· 25 = 8 units/day

      So, efficiency of β€˜S’ alone = 8 – 5 = 3 units/day

      Work done by β€˜S’ in 8 days = 3 Γ— 8 = 24 units

      Remaining work = 200 – 24 = 176 units

      Time taken by β€˜R’ to finish remaining work = 176 Γ· 5 = 35.2 days

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