Question
A can do a work in 30 hours while B can do it in 20
hours. If C is 60% more efficient than A and B together, then find the time taken by C alone to complete the work.Solution
ATQ, Total work = LCM of (30 and 20) = 60 units
Work by A in one hour = 60 ÷ 30 = 2 units
Work by B in one hour = 60 ÷ 20 = 3 units
Work by A and B together = 2 + 3 = 5 units
C is 60% more efficient → C’s work = 5 + (60% of 5) = 5 + 3 = 8 units
Time taken by C = 60 ÷ 8 = 7.5 hours
What is the position of T with respect to O?
What is the sum of present age of C and the one who is third to the right of C?
Which of the following statement is/are true?
I) T sits second to the right of W
II) Only one person sits between V and Y when counte...
How many persons sit between the one who sits to the immediate right of U and the one who sits to the immediate right of R?
Which of the following statements is/are not true regarding I?
Six friends (R, S, T, U, V and W) are sitting around a circle facing the center. Two friends sit between R and T. U sit second to the right of R and sit...
How many persons sit between D and V, if counted from the right of V?
In which of the following statement, the first and second persons are sitting opposite to each other in the final arrangement?
I)Â PW
...
Which of the following numbers will replace the question mark (?) in the given series?
5, 10, 30, 120, ?, 4320
Eight people are sitting around a circular table facing the centre. T is sitting between O and D. D is sitting third to the right of R. Z sits between ...
