Question
βAβ can complete a work in 20 days and is 20% more
efficient than βBβ. βAβ and βBβ start the work together, but βAβ leaves after 10 days. The remaining work is completed by βBβ alone in βxβ days. Find the value of βxβ.Solution
ATQ, Time taken by βBβ to complete the work = 1.2 Γ 20 = 24 days Let the total work = 120 units Efficiency of βAβ = 120/20 = 6 units/day Efficiency of βBβ = 120/24 = 5 units/day Work completed by βAβ and βBβ in 10 days = (6 + 5) Γ 10 = 110 units Therefore, x = (120 β 110)/5 = 2 days
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