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    Question

    β€˜A’ can complete a work in 20 days and is 20% more

    efficient than β€˜B’. β€˜A’ and β€˜B’ start the work together, but β€˜A’ leaves after 10 days. The remaining work is completed by β€˜B’ alone in β€˜x’ days. Find the value of β€˜x’.
    A 2 Correct Answer Incorrect Answer
    B 3 Correct Answer Incorrect Answer
    C 1 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ, Time taken by β€˜B’ to complete the work = 1.2 Γ— 20 = 24 days Let the total work = 120 units Efficiency of β€˜A’ = 120/20 = 6 units/day Efficiency of β€˜B’ = 120/24 = 5 units/day Work completed by β€˜A’ and β€˜B’ in 10 days = (6 + 5) Γ— 10 = 110 units Therefore, x = (120 – 110)/5 = 2 days

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