Question
βAβ can complete a work in 15 days and is 50% more
efficient than βBβ. βAβ and βBβ start working together and βAβ leaves after 8 days. The rest of the work is completed by βBβ alone in βxβ days. Find the value of βxβ.Solution
ATQ, Time taken by βBβ to complete the work = 1.5 Γ 15 = 22.5 days (round up to 23 days) Let the total work = 230 units Efficiency of βAβ = 230/15 = 15.33 units/day (round to 15 units/day) Efficiency of βBβ = 230/23 = 10 units/day Work completed by βAβ and βBβ in 8 days = (15 + 10) Γ 8 = 200 units Therefore, x = (230 β 200)/10 = 3 days
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