Question
βAβ can complete a work in 15 days and is 50% more
efficient than βBβ. βAβ and βBβ start working together and βAβ leaves after 8 days. The rest of the work is completed by βBβ alone in βxβ days. Find the value of βxβ.Solution
ATQ, Time taken by βBβ to complete the work = 1.5 Γ 15 = 22.5 days (round up to 23 days) Let the total work = 230 units Efficiency of βAβ = 230/15 = 15.33 units/day (round to 15 units/day) Efficiency of βBβ = 230/23 = 10 units/day Work completed by βAβ and βBβ in 8 days = (15 + 10) Γ 8 = 200 units Therefore, x = (230 β 200)/10 = 3 days
(350/?) = 23 + 33
(630 Γ· 35) Γ 2 + 144 = ? Γ 2
?/4 ÷ 9/? = 15% of 800 + `1(2/3)` × `1(1/5)` × 1/2
236.23-653.23+696.23=?
72 Γ 2 = ? + 104 β 14
36895 - 4256 - 2233 = ?Β
What will come in the place of question mark (?) in the given expression?
3.6 X 15 + 4.5 X 12 = 40% of (? - 50)? = 15% of 2400 + 140% of 4200 β 12 3Β
β121 + β961β β289 =?2
