Question
E and F can complete a task in 24 days together. E alone
can do it in 40 days. Find the time F alone would take.Solution
Let the total work be 120 units. {LCM (24 and 40)}
So, combined efficiency of 'E' and 'F' = 120 ÷ 24 = 5 units/day
Efficiency of 'E' = 120 ÷ 40 = 3 units/day
So, efficiency of 'F' = 5 - 3 = 2 units/day
So, time taken by 'F' to do the work alone = 120 ÷ 2 = 60 days
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