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Let the total work be 90 units. {LCM (18 and 30)}
So, combined efficiency of 'G' and 'H' = 90 ÷ 18 = 5 units/day
Efficiency of 'G' = 90 ÷ 30 = 3 units/day
So, efficiency of 'H' = 5 - 3 = 2 units/day
So, time taken by 'H' to do the work alone = 90 ÷ 2 = 45 days
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