Question
‘P’ is 25% more efficient than ‘Q’. ‘Q’
worked alone for 6 days and then ‘P’ finished the rest of the work in 4 days. How many days would ‘Q’ alone take to complete the entire work?Solution
ATQ,
Let efficiency of Q = 8x units/day Then efficiency of P = 8x × 1.25 = 10x units/day Work done by Q in 6 days = 8x × 6 = 48x units Work done by P in 4 days = 10x × 4 = 40x units Total work = 48x + 40x = 88x units Time taken by Q alone to complete the whole work = 88x / 8x = 11 days
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