Question
R and S take 10 days and 15 days respectively to complete a task alone. If they alternate work every day starting with R, how much time will it take to finish the job?
Solution
ATQ,
Total work = 30 units (LCM of 10 and 15)
R’s efficiency = (30 ÷ 10) = 3 units/day
S’s efficiency = (30 ÷ 15) = 2 units/day
In 2 days = 3 + 2 = 5 units
Time = (30 ÷ 5) × 2 = 12 days
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