Question
Anand and Manav can collaboratively finish a task in
{40/3} days, while Anand alone requires 24 days to complete the same task. Given that Prachi's efficiency is 25% lower than Manav's, determine the number of days it will take Prachi to complete the work on her own.Solution
Let the total work be 120 units (LCM of (40/3) and 24) . Combined efficiency of Anand and Manav together = 120 ÷ (40/3) = 9 units/day Efficiency of Anand = (120/24) = 5 units/day So, efficiency of Manav = 9 - 5 = 4 units/day Efficiency of Prachi = 0.75 X 4 = 3 units/day Required time taken = (120/3) = 40 days
If p = 24 - q - r and pq + r(q + p) = 132, then find the value of (p² + q² + r²).
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
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Find the value of the given expression-
(4x+4 -5× 4x+2) / 15×4x – 22×4x
If 4x² + y² = 40 and x y = 6, then find the value
of 2x + y?
If p = 40 - q - r and pq + r(q + p) = 432, then find the value of (p² + q² + r²).
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
If x + y = 4 and (1/x) + (1/y) = 24/7, then the value of (x3 + y3).
- If p = 20 - q - r and pq + r(p + q) = 154, then find the value of (p² + q² + r²).
If a = (√2 - 1)1/3, then the value of (a-1/a)3 +3(a-1/a) is:
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