Question
βPβ can complete 40% of a
task in 24 days, while βQβ can complete 25% of the task in 20 days. How long will it take approximately for βPβ and βQβ together to finish 75% of the entire work?Solution
ATQ, Time taken by βPβ to complete the whole task = 24/0.40 = 60 days Time taken by βQβ to complete the whole task = 20/0.25 = 80 days Let the total amount of work = 480 units Amount of work done by βPβ in one day = 480/60 = 8 units Amount of work done by βQβ in one day = 480/80 = 6 units Combined work per day = 8 + 6 = 14 units Desired time = (0.75 Γ 480)/14 = 25.71 days (approximately 25.7 days)
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